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lys-0071 [83]
3 years ago
13

The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric sh

ock. What is the mass of the sample of water? *DO NOT put units in your answer.**
Please help guys
Chemistry
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

33.8.

Explanation:

Hello,

In this case, since the used equation is:

Q=mCp(T_2-T_1)

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

m=\frac{Q}{Cp(T_2-T_1)}

Thus, the mass turns out:

m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g

And without units:

33.8.

Best regards.

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                2          :             1

              0.05       :          1/2×0.05=0.025 mol

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              3               :              3

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