Question

The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric shock. What is the mass of the sample of water? *DO NOT put units in your answer.**
Please help guys

Answer 1

Answer:

33.8.

Explanation:

Hello,

In this case, since the used equation is:

$Q=mCp(T_2-T_1)$

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

$m=\frac{Q}{Cp(T_2-T_1)}$

Thus, the mass turns out:

$m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g$

And without units:

33.8.

Best regards.