Answer:
a material used to prop open the underground cracks from which the oil and natural gas can then be harvested during the fracturing process.
Explanation:
Answer:
[N2] = [O2] = 0.841M
And [NO] = 0.00172M
Explanation:
The equilibrium constant of this reaction, Kc, is:
Kc = 2400 = [N2] [O2] / [NO]²
<em>Where [] are the equilibrium concentration of each specie.</em>
<em />
The initial concentration of [N2] = [O2] = 0.850M. The equilibrium will shift to the left in order to produce NO. The equilibrium concentrations are:
[N2] = [O2] = 0.850M - X
And [NO] = 2X
Replacing:
2400 = [0.850-X]² / [2X]²
9600X² = 0.7225 - 1.7 X + X²
0 = 0.7225 - 1.7 X - 9599X²
Solving for X:
X = -0.0088M. False solution, there is no negative concentrations.
X = 0.00859M. Right solution.
Replacing:
[N2] = [O2] = 0.850M - 0.00859M
And [NO] = 2*0.00859M
[N2] = [O2] = 0.841M
And [NO] = 0.00172M
Answer:
C. 0.72 M
Explanation:
To calculate the molarity use the following equation, C=n/V
You have the molar number n which is 0.702 and the volume 0.98 L
Replace those numbers in the formula C=0.702/0.98= 0.72 M
Answer:
CaO is a binary compound.
<span>Answer
is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643
1/s.
k</span>₂ = 0,00828
1/s.
T₁ = 622 K.
T₂ = 666 K.
R = 8,3145 J/Kmol.
1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K =
0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>