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olga55 [171]
3 years ago
7

Which of these could be a physical change?

Chemistry
2 answers:
BigorU [14]3 years ago
7 0

Answer:

C

Explanation:

A physical change is when the form of the matter is just altered. While a chemical change results from a chemical reaction. No reaction is happening during the mixing of the two colors [nothing is boiling, freezing, evaporating, melting ext.] , but after you mix them the end result does look different. That only because we changed the physical properties of it.

(B is not a physical change because the baking powder inside of the cake must under go a reaction that causes the cake to rise. )

olga nikolaevna [1]3 years ago
3 0

Answer:

C. A blue liquid and a yellow liquid mix and make a green liquid.

Explanation:

A physical change is a change in which chemically a substance remains the same but a change in state of matter may occur. It is a reversible change i.e. the substance can be converted into the original state even after the change has occurred. As per option c even if a blue liquid has been mixed with a yellow liquid to produce a green liquid we can still separate both the liquids using a physical method of separation to get the original liquids back.

Other options are wrong because they are examples of chemical change in which the change is irreversible and we can never get the original substance back by any means because a reaction has changed the substance entirely.

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Identify the power of ten that defines each of these prefixes. Input your answers as 10 x where x is the power of ten. nano- ___
Gemiola [76]

<u>Answer:</u> The quantity of every prefix is written below as a power of ten.

<u>Explanation:</u>

In the metric system of measurement, the name of multiples and subdivision of any unit is done by combining the name of the unit with the prefixes.

<u>For Example:</u> deka, hecto and kilo means 10, 100 and 1000 respectively. Deci, centi and milli means one-tenth, one-hundredth, and one-thousandth respectively.

The quantity of these prefixes are written as the power of 10.

For the given prefixes:

<u>Nano:</u>  The quantity will be 10^{-9}

<u>Kilo:</u>  The quantity will be 10^3

<u>Centi:</u>  The quantity will be 10^{-2}

<u>Micro:</u>  The quantity will be 10^{-6}

<u>Milli:</u>  The quantity will be 10^{-3}

<u>Mega:</u>  The quantity will be 10^6

Hence, the quantity of every prefix is written above as a power of ten.

7 0
3 years ago
Calculate the volume occupied by 272g
cupoosta [38]

The answer for the following problem is mentioned below.

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

Explanation:

Given:

mass of methane(CH_{4}) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of  methane(CH_{4}) = 16.0​  grams

We know;

According to the ideal gas equation,

<u><em>P × V = n × R × T</em></u>

here,

n = m÷M

n =272 ÷ 16

<u><em>n = 17 moles</em></u>

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

<u><em></em></u>

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6 0
3 years ago
Aluminum fluoride contains only aluminum and fluorine. what is the formula for this compound?
attashe74 [19]
AlF3 would be the answer
3 0
3 years ago
Read 2 more answers
I NEED HELP ASAP !!!!!!!!!!!!!!!!!!!!!1
Karolina [17]

Answer:

true im pretttyyy sure

Explanation:

bcuz the stronger the intermolecular forces the higher the boiling point :3

6 0
2 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
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