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murzikaleks [220]
3 years ago
13

A company has a monthly profit, or gain, of $6,400. The next month they have a loss of $4,700.

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer:

6400-(-4700)

Step-by-step explanation:

Given,

The profit in present month = $ 6,400,

Also, there is a loss of $ 4,700 in the next month,

So, the profit in the next month = -$ 4,700,

Note : Negative sign shows the loss.

Hence, the difference in profit between the two months

= Profit in present month - profit in next month

=6400-(-4700)

Which is the required expression.

katrin [286]3 years ago
6 0

For the first month we have the following profit or benefit:

$ 6,400

For the second month we have the following loss:

$ 4,700

Therefore, the net benefit is given by:

Net Profit = Profit - Lost

Substituting values we have:

Net profit = 6400 - 4700

Answer:

An expression that you would use to find the difference in profit between the two months is:

Net profit = 6400 - 4700

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Answer:

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Step-by-step explanation:

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Now add this to the other fraction:

\frac{9}{12} + \frac{7}{12} = \frac{16}{12}

This can be simplified down by dividing both the numerator and denominator by 4:

\frac{4}{3}

Which now simplifies the original equation to:

\frac{y}{8}  = \frac{4}{3}

Remove the y out of the fraction:

\frac{1}{8}y = \frac{4}{3}

Now multiply both sides by 8:

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Hope this helps!

5 0
3 years ago
Read 2 more answers
Suppose an airline policy states that all baggage must be box shaped with a sum of length, width, and height not exceeding 174 i
Leya [2.2K]

Answer:

The square-based box with the greatest volume under the condition that the sum of length, width, and heigth does not exceed 174 in is a cube with each edge of 58 in and a volume of 195112 in^{3}

Step-by-step explanation:

For this problem we have two constraints, that are as follows:

1) Sum of length, width, and heigth not exceeding 174 in

2) Lenght and width have the same measure (square-based box)

We know that volume is equal to the product of all three edges, and with the two conditions into account we have the next function:

V=(w^{2})(174-2w)\\V=174w^{2}-2w^{3}

The interval of interest of the objective function is [0, 87]

This problem requieres that we maximize the function that defines the volume. We start calculating the derivative of the function, wich is:

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We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.

So we find the value in wich the derivative equals zero:

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The first value (w=0) will leave us with a 'height-only box', so the answer must be w=58 in

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Answer:

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