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sveta [45]
3 years ago
5

If you are given only the measurements of the three angles of a right triangle, can you find the lengths of the three sides?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

No

Because you can't find any of the length if you don't have two other lengths

Step-by-step explanation:

study cosine rule and sine rule

you use cosine rule when you have one angle in-between two length

while you use sine rule when you have two angles and one length

just study cosine rule and sine rule you will understand what am saying

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1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
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