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Lana71 [14]
3 years ago
13

What substitution should be used to rewrite 4x^4-21x^2+20=0 as a quadratic function?

Mathematics
2 answers:
pogonyaev3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Let u = x² ( choice of variable is flexible ), then

4u² - 21u + 20 = 0 ← expressed as a quadratic

This can now be solved for u and converted back into terms of x

Ipatiy [6.2K]3 years ago
3 0

Answer:

refer the explanation

Step-by-step explanation:

this question can be written as

X^2=y

so,x^4=y^2

so it will be 4y^2-21y+20=0

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Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.
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We are given a function f ( x ) defined as follows:

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Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be:

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Step-by-step explanation:

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