What substitution should be used to rewrite 4x^4-21x^2+20=0 as a quadratic function?
2 answers:
Answer:
see explanation
Step-by-step explanation:
Let u = x² ( choice of variable is flexible ), then
4u² - 21u + 20 = 0 ← expressed as a quadratic
This can now be solved for u and converted back into terms of x
Answer:
refer the explanation
Step-by-step explanation:
this question can be written as
X^2=y
so,x^4=y^2
so it will be 4y^2-21y+20=0
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Step-by-step explanation: