PH can be calculated using the following equation
pH = -log [H₃O⁺]
for apple juice the hydronium /hydrogen ion concentration is 0.0003
pH = -log (0.0003)
pH = 3.5
correct answer is C
For ammonia
pH = -log (3.1 x 10⁻⁹)
pH = 8.5
answer should be 8.5
Answer:
16.5 ft by 25.5 ft
Step-by-step explanation:
Let w represent the width of the garden in feet. Then w+9 is the garden's length, and w(w+9) represents its area.
The surrounding walkway adds 8 feet to each dimension, so the total area of the garden with the walkway is ...
(w+8)(w+9+8) = w^2 +25w +136
If we subtract the area of the garden itself, then the remaining area is that of the walkway:
(w^2 +25w +136) - (w(w+9)) = 400
16w + 136 = 400 . . .simplify
16w = 264 . . . . . . . . subtract 136
264/16 = w = 16.5 . . . . . width of the garden in feet
w+9 = 25.5 . . . . . . . . . . .length of the garden in feet
Answer:
Step-by-step explanation:
A. The front elevation of the pyramid in the direction of the arrow is herewith attached to this answer.
B. Base of the pyramid is a square of side 12 cm.
The height of the pyramid is 8 cm.
Slant height, XT, is 10 cm.
The total surface area of the pyramid can be determined by adding the surface areas that make up the shape.
Area of the triangular face =
× base × slant height
=
× 12 × 10
= 60 
Area of the square base = length × length
= 12 × 12
= 144 
Total surface area of the pyramid = area of the base + 4 (area of the triangular face)
= 144 + 4(60)
= 144 + 240
= 384 
Therefore, total surface area of the pyramid is 384
.
Answer:
Step-by-step explanation:
The number of adults in the family that is going to the amusement park is 2.
The number of children in the family that is going to the amusement park is 4.
Admission is a 21 point 75 for adults and 15 point 25 for children. This means that the admission cost for each adult is 21.75 and the admission cost for each adult is 15.25. Therefore,
The total cost of admission for the 2 adults would be
21.75 × 2 = 43.5
The total cost of admission for the 4 children would be
15.25 × 4 = 61
Therefore, the total cost of the families admission would be
43.5 + 61 = 104.5