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3 years ago

Find the missing dimension. Use the scale factor 1: 15. Door Model Height 10 in Actual

Mathematics

1 answer:

anygoal [31]3 years ago

5 0

Answer:

The answer is "150 unit"

Step-by-step explanation:

scale factor = 1:15

height = 10

dimension =?

let dimension = x

$\Rightarrow \frac{10}{x} = \frac{1}{15} \\\\\Rightarrow 150 = x\\\\\Rightarrow x= 150 \ units$

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Soloha48 [4]

The grade would be 87%

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3 years ago

A company has determined that its weekly profit is a function of the number of items that it sells. Which equation could represe

Vilka [71]

Eliminate answer choices C and D immediately, since we are not looking to solve for either x or x^2; rather, we want the weekly profit (y) when the company sells x items. Eliminate choice A, because we are not looking to calculate the profit squared. This process of elimination of unsuitable answers leaves us with answer choice B, in which y is the the weekly profit in thousands of dollars, y, when the company sells x items.

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3 years ago

Read 2 more answers

The maker of an automobile advertises that it takes 12 seconds to accelerate from 20 kilometers per hour to 65 kilometers per ho

sp2606 [1]

Answer:

The acceleration is 1.0416 m/ $s^{2}$

Step-by-step explanation:

In order to solve this problem we first need to know the formula for acceleration which is the following.

$acceleration = \frac{final.velocity - initial.velocity}{final.time - initial.time}$

Since the time acceleration is calculated as $m/s^{2}$ we need to convert the km/h into m/s. Since 1km = 1000m and 1 hour = 3600 seconds, then

$\frac{20*1000 }{3600s} = \frac{20,000m}{3600s} = \frac{20m}{3.6s}$

**Dividing numerator and denominator by 1000 to simplify**

$\frac{65*1000 }{3600s} = \frac{65,000m}{3600s} = \frac{65m}{3.6s}$

**Dividing numerator and denominator by 1000 to simplify**

Now we can plug in the values into the acceleration formula to calculate the acceleration.

$acceleration = \frac{\frac{65m}{3.6s}-\frac{20m}{3.6s} }{12s-0s}$

$acceleration = \frac{\frac{45m}{3.6s}}{12s}$

$acceleration = \frac{\frac{12.5m}{s}}{12s}$

$acceleration = \frac{\frac{1.0416m}{s}}{s}$

Finally we can see that the acceleration is 1.0416 m/ $s^{2}$

8 0

3 years ago

Blake is a member of a golf club. When he became a member, he deposited money into his club account. For each round of golf that

Leno4ka [110]

Answer:

D) Blake's account initially had $320, which is decreasing at the rate of $20 per round.

Step-by-step explanation:

Here, according to the question:

x: The total number of golf rounds played

y: Represents the amount, in dollars, left in his account after playing x rounds

Let as assume A is the amount deposited initially.

y = A - n x here n : rate of each round played

Also, here

if x = 2, then y = 280

if x =4, then y = 240

If x = 2 and y = 280, then:

y = A - n x ⇒ 280 = A - 2 n ... (1)

If x = 4 and y = 240, then:

y = A - n x ⇒ 240 = A - 4 n ... (2)

Solving (1) and (2) by (1) - (2), we get:

40 = 2 n or, n = 20

Putting n = 20 in 280 = A - 2 n, we get: A = 280 + 2(20) = 320

⇒ A = $320, n = $20

⇒ The amount initially deposited is $320 and the rate per round is $20

Hence ,Blake's account initially had $320, which is decreasing at the rate of $20 per round.

4 0

3 years ago

What is the 4th term in a geometric sequence for which a1=10 and r=.5

OlgaM077 [116]

First term a1=10 & r=0.5 & n=4

The formula to find the term =a(n) = a(1)*(r)^(n-1)

a(4th)=10*(0.5)^3 =1.25

proof:

a1=10

a2=10*0.5=5

a3= 5*0.5 = 2.5

a4= 2.5*0.5=1.25

3 0

3 years ago