Answer:
No :) here this is my channel name jshdhebejdb
Answer:
Explanation:
i) On a cold day, Capacity = (66 X 910 X 10∧-9) F
Charge, Q = (66 X 910 X 10∧-9) X 5050 = 0.30 Columb
Current, I= 5050/131013 = 0.039 Amp (where Resistance = 131013 ohms)
Time, t= 0.30/0.039 = 7.7 seconds
ii) On a humid day, Capacity = (77 X 910 X 10∧-9) F
Charge, Q = ( 77 X 910 X 10∧-9) X 5050 = 0.35 Columb
Current, I= 5050/6106 = 0.83 Amp ( where Resistance = 6106 ohms)
Time, t= 0.35/0.83 = 0.42 h or 0.42 X 60 mins = 25 mins
Answer:
FALSE....john has no idea what hes talking about. i knew this was false yet i looked it up and got it wrong anyway because of john its freaking false
Explanation:
Answer:
I personally use a alienware
Explanation:
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n;
double average,sum=0,x;
cout<<"enter the Value of N:";
// read the value of N
cin>>n;
cout<<"enter "<<n<<" Numbers:";
// read n Numbers
for(int a=0;a<n;a++)
{
cin>>x;
// calculate total sum of all numbers
sum=sum+x;
}
// calculate average
average=sum/n;
// print average
cout<<"average of "<<n<<" Numbers is: "<<average<<endl;
return 0;
}
Explanation:
Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.
Output:
enter the Value of N:5
enter 5 Numbers:20.5 19.7 21.3 18.6 22.1
average of 5 Numbers is: 20.44
