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RideAnS [48]
2 years ago
11

Which of the following statements are true of software engineers? Check all of the boxes that apply. They are responsible for wr

iting programming code. They are usually strong problem-solvers. They spend most of their work hours running experiments in a laboratory. They must hold advanced degrees in computer science.
Computers and Technology
2 answers:
Zina [86]2 years ago
4 0

Answer:

First two statements: yes. Last two: not so much.

But many of the better ones do have advanced degrees, but some don't.

The laboratory statement is silly; they sit behind a set of screens figuring out stuff and writing code.

saw5 [17]2 years ago
3 0

Answer:

They are responsible for writing programming code.

They are usually strong problem-solvers.

Explanation:

$$$$

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Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
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Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

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