Question

Suppose a population is carrying a condition controlled by two alleles: P (dominant) and p (recessive). Only homozygous individuals that have two copies of the recessive allele have the condition. If the p allele is found in 15 percent of the population, what's the frequency of the PP genotype?
A. 25.5 percent
B. 72.25 percent
C. 2.25 percent
D. 12.75 percent

Answer 1

The answer is B. 72.25 percent.

The Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles, and p², q² and 2pq are the frequencies of the genotypes.

The p allele (q) is found in 15% of the population:
q = 15% = 15/100
Thus, q = 0.15

To calculate the P allele frequency (p), the formula p + q = 1 can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, p = 0.85

Knowing the frequency of the P allele (p), it is easy to determine the frequency of the PP genotype (p²):
p² = 0.85² = 0.7225

Expressed in percentage, p² = 72.25%.