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3 years ago

How to complete the problem

Mathematics

1 answer:

Fittoniya [83]3 years ago

8 0

For step 2 it should be x^2-16x+73

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How long does it take for a car traveling at a speed of 50.0 miles per hour to travel 300 feet?

beks73 [17]

We know, Time = distance / speed
t = 0.0568182 / 50 [ 300 Feet = 0.0568182 miles ]
t = 0.001136 * 3600 s
t = 4.09 sec

In short, Your Answer would be 4.09 Seconds

Hope this helps!

3 0

3 years ago

Five year old Michelle weighs 75 decagrams. What is her weight in centigrams?

Svet_ta [14]

It should be 75000. I don’t know. I looked this up but I still hope this helps!

3 0

3 years ago

Read 2 more answers

Michael's bank account opened with $100. 5 weeks after opening, his account balance was $250.

cupoosta [38]

I am pretty sure it is $400. sorry if i’m wrong

8 0

3 years ago

What is the value of x, when 10(x + 2) = 5(x + 8)?

tatuchka [14]

The value of x is 4. The steps to solving the equation are to use distributive property first so that the equation then looks like this: 10x+20=5x+40
Next you would combine like terms and then the equation would look like this: 5x+20=40
Then you would use the subtraction property of equality to subtract 20 from 40 so your equation will now look like this: 5x=20
Then you use the division property of equality to divide 20 by 5 to get x=4

7 0

3 years ago

Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind

Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

The transformation T is; a dilation transformation with a scale factor of 2, D₂

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

$\displaystyle \frac{AB}{A'B'} = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}$

Which gives;

$\displaystyle \frac{AB}{A'B'} = \frac{AB}{2 \cdot AB} = \frac{1}{2}$

A'B' = 2·AB

Therefore;

Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and T is a dilation transformation with a scale factor of 2, D₂

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0

2 years ago