<span>area = (1/2) · b · (6 · h + sqrt(3) · b) hope that helped</span>
Answer:
30
Step-by-step explanation:
0.5 * unknown number = 15
but
we see unknown number = 15 / 0.5 = 30
(3) Differentiating both sides of

with respect to <em>x</em> gives

Solve for d<em>y</em>/d<em>x</em> :

Then the slope of the tangent line to the curve at (1, 9) is

The equation of the tangent line would then be
<em>y</em> - 9 = -2/3 (<em>x</em> - 1) ==> <em>y</em> = -2/3 <em>x</em> + 29/3
(4) The slope of the tangent line to

at a point <em>(x, y)</em> on the curve is

When <em>x</em> = -1, we have a slope of 2/3, so
-(2<em>a</em> + 1)/(-1 - 2)² = 2/3
Solve for <em>a</em> :
-(2<em>a</em> + 1)/9 = 2/3
2<em>a</em> + 1 = -18/3 = -6
2<em>a</em> = -7
<em>a</em> = -7/2
Answer:
the scale factor is 2.
Step-by-step explanation:
corresponding sides of the triangle are proportionate. mn and rs correspond. 6/3=2
Answer:
These Lines will be parallel.
Step-by-step explanation:
You have to find the slope of each line. For (1,1) and (3,3) the slope is 1 and for Line 2 the slope is also 1. (let me know if you want me to show the work for slope). To have parallel lines the slopes have to be the same and y-ints have to be different. Here the slopes are the same and in Line 1 the yint is (0,0) which is different than Line 2. Therefor the Lines are parallel.
Sorry if im wrong!. Hope this helps