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velikii [3]
3 years ago
10

Is 1/3 greater than less than or equal to 0.33

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0

0.33 is less than 1/3

posledela3 years ago
3 0
0.33 is less than 1/3
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The The graph of g(x) is the result of translating the graph of f(x) = 3x six units to the right. What is the equation of g(x)?
kolbaska11 [484]

<u>Translation</u> the <u>graph</u> of the <u>function</u> y=f(x) a units <u>to the right</u> gives you the function y=f(x-a).

If the graph of the function f(x)=3^x is translated 6 units to the right, then the function becomes

g(x)=f(x-6)=3^{x-6}.

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4 years ago
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Factors of 30 add up to 9. what are they?
Daniel [21]


1,2,3,5,6,10,15,30

think that's right, hope this helps!

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3 years ago
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In how many ways can 100 identical chairs be distributed to five different classrooms if the two largest rooms together receive
Eva8 [605]

Answer:

There are 67626 ways of distributing the chairs.

Step-by-step explanation:

This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).

The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, {n+k-1 \choose k-1} .

For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is {50+2-1 \choose 2-1} = 51 .

For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have {50+3-1 \choose 3-1} = {52 \choose 2} = 1326 ways of making the distribution.

As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.

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3 years ago
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frozen [14]

Answer:

A- 15-5 is the same

Step-by-step explanation:

15 + (3-8)

15 + (-5)

15-5

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4 years ago
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Find the sum of the first 30 terms of the sequence below. an=4n+1
dmitriy555 [2]
That would be 1,890.
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