The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Answer:
is there anymore to the question?
Step-by-step explanation:
About 99.7% of vehicles whose speeds are between 59 miles per hour and 77 miles per hour.
Empirical rule states that for a normal distribution, 68% lie within one standard deviations, 95% lie within two standard deviations, and 99.7% lie within three standard deviations of the mean.
Given that mean (μ) = 68 miles per hour, standard deviation (σ) = 3 miles per hour.
68% lie within one standard deviation = (μ ± σ) = (68 ± 3) = (65, 71).
Hence 68% of the vehicle speed is between 65 miles per hour and 71 miles per hour.
95% lie within two standard deviation = (μ ± 2σ) = (68 ± 2*3) = (62, 74).
Hence 95% of the vehicle speed is between 62 miles per hour and 74 miles per hour.
99.7% lie within three standard deviation = (μ ± 3σ) = (68 ± 3*3) = (59, 77).
Hence 99.7% of the vehicle speed is between 59 miles per hour and 77 miles per hour.
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Answer:
Jason will pay $50.05 in taxes
Step-by-step explanation:
9514 1404 393
Answer:
(a) none of the above
Step-by-step explanation:
The largest exponent in the function shown is 2. That makes it a 2nd-degree function, also called a quadratic function. The graph of such a function is a parabola -- a U-shaped curve.
The coefficient of the highest-degree term is the "leading coefficient." In this case, that is the coefficient of the x² term, which is 1. When the leading coefficient of an even-degree function is positive, the U curve has its open end at the top of the graph. We say it "opens upward." (When the leading coefficient is negative, the curve opens downward.)
This means the bottom of the U is the minimum value the function has. For a quadratic in the form ax²+bx+c, the horizontal location of the minimum on the graph is at x=-b/(2a). This extreme point on the curve is called the "vertex."
This function has a=1, b=1, and c=3. The minimum of the function is where ...
x = -b/(2·a) = -1/(2·1) = -1/2
This value is not listed among the answer choices, so the correct choice for this function is ...
none of the above
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The attached graph of the function confirms that the minimum is located at x=-1/2
_____
<em>Additional comment</em>
When you're studying quadratic functions, there are few formulas that you might want to keep handy. The formula for the location of the vertex is one of them.
