7/4 * 301/2 (changed into mixed numbers)
2107/8
263.375
C
because when you change 3 into a mixed fraction its 263*8+3/8
263.375
#1
Answer:
B = 12800 grams or 12kg 800 grams.
Step-by-step explanation:
Let the two puppies be A and B respectively.
Translating the word problem into an algebraic expression, we have;
A + B = 22kg 300g
A = 9kg 500g
Conversion;
1 Kilograms = 1000 grams.
9kg 500g = 9*1000 + 500 = 9500 grams
22kg 300g = 22*1000 + 300 = 22300 g
Substituting into the above formula, we have;
9500 + B = 22300
B = 22300 - 9500
B = 12800 grams or 12kg 800 grams
The mean of this test will be 57.
<h3>What is Standard Deviation and Mean?</h3>
A standard deviation (or σ) is a measure of how dispersed the data is in relation to the mean.
The mean can be used to get an overall idea, or picture, of the data set.
Let Mean be 'm'
and standard deviation= 
So, m-2
=49
and, m +
=61
Solving the above two equation we get

Now, m= 61-
= 61-4
= 57
So , the mean of this test will be =57
Learn more about mean and standard deviation here:
brainly.com/question/16030790
#SPJ1
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required lengths are not given.
I will use the following data set to answer the question.

First, is to determine the range of the dataset



Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval




<em>So, we use 4 classes</em>
Plot the frequency distribution table as follows:

<em>See attachment for histogram</em>
Answer:
3.9 percent
Step-by-step explanation:
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