power=voltsxamps=watts.
12=3xamps
4 amps
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A. To increase the current, decrease the resistance.
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r=v/i = 53/7
Answer:
The intensity of light from the 1mm from the central maximu is 
Explanation:
From the question we are told that
The wavelength is 
The width of the slit is 
The distance from the screen is 
The intensity at the central maximum is 
The distance from the central maximum is 
Let z be the the distance of a point with intensity I from central maximum
Then we can represent this intensity as
![I = I_o [\frac{sin [\frac{\pi * w * sin (\theta )}{\lambda} ]}{\frac{\pi * w * sin (\theta )}{\lambda } } ]^2](https://tex.z-dn.net/?f=I%20%3D%20I_o%20%5B%5Cfrac%7Bsin%20%5B%5Cfrac%7B%5Cpi%20%2A%20w%20%2A%20sin%20%28%5Ctheta%20%29%7D%7B%5Clambda%7D%20%5D%7D%7B%5Cfrac%7B%5Cpi%20%2A%20w%20%2A%20sin%20%28%5Ctheta%20%29%7D%7B%5Clambda%20%7D%20%7D%20%5D%5E2)
Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e
if the angle between the the light at z and the central maximum is small
Then 
Which implies that
substituting this into the equation for the intensity
![I = I_o [\frac{sin [\frac{\pi w}{\lambda} \cdot \frac{z}{D} ]}{\frac{\pi w z}{\lambda D\frac{x}{y} } } ]](https://tex.z-dn.net/?f=I%20%3D%20I_o%20%5B%5Cfrac%7Bsin%20%5B%5Cfrac%7B%5Cpi%20w%7D%7B%5Clambda%7D%20%5Ccdot%20%5Cfrac%7Bz%7D%7BD%7D%20%20%5D%7D%7B%5Cfrac%7B%5Cpi%20w%20z%7D%7B%5Clambda%20D%5Cfrac%7Bx%7D%7By%7D%20%7D%20%7D%20%5D)
given that 
We have that
![I = I_o [\frac{sin[\frac{3.142 * 0.45*10^{-3}}{(620 *10^{-9})} \cdot \frac{1*10^{-3}}{3} ]}{\frac{3.142 * 0.45*10^{-3}*1*10^{-3} }{620*10^{-9} *3} } ]^2](https://tex.z-dn.net/?f=I%20%3D%20I_o%20%5B%5Cfrac%7Bsin%5B%5Cfrac%7B3.142%20%2A%200.45%2A10%5E%7B-3%7D%7D%7B%28620%20%2A10%5E%7B-9%7D%29%7D%20%5Ccdot%20%5Cfrac%7B1%2A10%5E%7B-3%7D%7D%7B3%7D%20%5D%7D%7B%5Cfrac%7B3.142%20%2A%200.45%2A10%5E%7B-3%7D%2A1%2A10%5E%7B-3%7D%20%7D%7B620%2A10%5E%7B-9%7D%20%2A3%7D%20%7D%20%5D%5E2)
![=I_o [\frac{sin(0.760)}{0.760}] ^2](https://tex.z-dn.net/?f=%3DI_o%20%5B%5Cfrac%7Bsin%280.760%29%7D%7B0.760%7D%5D%20%5E2)
Answer:
x = 2.69 cm
Explanation:
We are given ;
Density of oil; ρ_oil = 924 kg/m³
Density of wood; ρ_wood = 970 kg/m³
h = 3.79cm
Density of water ( ρ_water) has a constant value of 1000 kg/m³
At equilibrium position, we have;
ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0
This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.
x is the distance below the interface between the two liquids is the bottom of the block.
Thus, let's make x the subject;
x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h
Plugging in the relevant values to get ;
x = [(970 - 924)/(1000 - 924)] x 3.79
x = (54/76) x 3.79 = 2.69cm
Sum of all forces = mass * acceleration
Ft= tension force
Fw= force of gravity (Fw= mass* acceleration of gravity which is 9.8 this only applies to force of gravity)
Ft- Fw = 0 (there is no acceleration)
Ft = Fw
Ft= m*g
Ft= 0.250kg*9.8m/s
Ft= 2.45N
Answer:
Good question
Explanation:
The reason is that walls are made up of more than just atoms. Walls are built up from many things, so with this being said we cannot walk through the walls
PPs why do or should anyone want to walk through walls?
