The correct answer is D. magnitude; direction
We know this thanks to Newton's 3rd law
Hope that helps!!
Answer:
Explanation:
Mass: M, Length: L.
The formula that gives center of mass is
In the case of a non-uniform mass density, this formula converts to
where the denominator is the total mass and the nominator is the mass times position of each point on the rod.
We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:
Here x's are cancelled. Otherwise, the denominator would be zero.
Complete question is;
Which of the following can be reduced to a single number in standard form?
A) 3√3 + 5√8
B) 2√5 + 5√45
C) √7 + √9
D) 4√2 + 3√6
Answer:
Only option B) 2√5 + 5√45 can be reduced to a single number
Explanation:
A) For 3√3 + 5√8;
Let's simplify it to get;
3√3 + 5√(4 × 2)
From this, we get;
3√3 + (5 × 2)√2 = 3√3 + 10√2
This is 2 numbers and not a single number. Thus it can't be reduced to a single number in standard form.
B) 2√5 + 5√45
Simplifying to get;
2√5 + 5√(9 × 5)
This gives;
2√5 + (5 × 3)√5 = 2√5 + 15√5
Adding the surds gives;
17√5.
This is a single number and thus can be reduced to a single number
C) For √7 + √9
Simplifying, to get;
√7 + 3.
This is 2 numbers and not a single number. Thus it can't be reduced to a single number in standard form.
D) 4√2 + 3√6
Thus can't be simplified further because both numbers inside the square root don't have factors that are perfect squares.
Thus, it remains 2 numbers and not a single number and can't be reduced to a single number in standard form.
Molecular mass may be calculated by taking the atomic mass of each element present and multiplying it by the number of atoms of that element in the molecular formula. Then, the number of atoms of each element is added together. This value may be reported as a decimal number or as 16.043 Da or 16.043 amu.
It's average speed during that 26 seconds was about 4.77 m/s. Without seeing the graph, we can't tell if it was going faster or slower at any particular time during that period. All we can tell is its average for the full interval.
