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Gnom [1K]
3 years ago
13

assuming that tide duration from low tide to high tide is 6 hours and 25 minutes, going from a high of 3.21ft and down to a low

of 0.20ft what is the lapse rate per hour of the tide?
Mathematics
1 answer:
mixer [17]3 years ago
4 0
To answer this you will need to write the ratio of difference in the tides over the amount of time that goes by.

1. 3.21 ft - 0.20 ft= 3.01 ft change.
2. 3.01 change over 6 5/12 hr.
3. Divide these to find the lapse rate per hour. This is about 0.47 ft per hour.
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What is x and what is y in 4x-2y=4
Fed [463]

Answer:

x = 1/2y + 1

y = 2x - 2

Step-by-step explanation:

Let's solve for x.

4x−2y=4

Step 1: Add 2y to both sides.

4x−2y+2y=4+2y

4x=2y+4

Step 2: Divide both sides by 4.

4x

4

=

2y+4

4

x=

1

2

y+1

Answer:

x=

1

2

y+1

Let's solve for y.

4x−2y=4

Step 1: Add -4x to both sides.

4x−2y+−4x=4+−4x

−2y=−4x+4

Step 2: Divide both sides by -2.

−2y

−2

=

−4x+4

−2

y=2x−2

Answer:

y=2x−2

Hope this helps!

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