Question

The equation below describes a circle. What are the coordinates of the center

Answer 1

The equation of a circle: $(x-h)^2 + (y-k)^2 = r^2 \ Where \ (h, k) \ the \ origin \ of \ the \ circle\\(x-6)^2 + (y+5)^2 = 152 => C(6, -5)$

Answer 2

Answer:

$(6,-5)$

Step-by-step explanation:

The general equation for a circle is:

$(x-h)^2+(y-k)^2=r^2$

where $(h,k)$ is the center of the circle, and $r$ is the radius.

The equation we have is:

$(x-6)^2+(y+5)^2=152$

we can also write this as follows:

$(x-6)^2+(y-(-5))^2=152$

this way we can see that

$h=6$

and

$k=-5$

so, since the center of the circle is at

$(h,k)$

substituting the values:

$(6,-5)$ this are the coordinates of the center of the circle