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Helen [10]
3 years ago
13

The equation below describes a circle. What are the coordinates of the center

Mathematics
2 answers:
Rzqust [24]3 years ago
3 0

The equation of a circle: (x-h)^2 + (y-k)^2 = r^2 \ Where \ (h, k) \ the \ origin \ of \ the \ circle\\(x-6)^2 + (y+5)^2 = 152 => C(6, -5)

QveST [7]3 years ago
3 0

Answer:

(6,-5)

Step-by-step explanation:

The general equation for a circle is:

(x-h)^2+(y-k)^2=r^2

where (h,k) is the center of the circle, and r is the radius.

The equation we have is:

(x-6)^2+(y+5)^2=152

we can also write this as follows:

(x-6)^2+(y-(-5))^2=152

this way we can see that

h=6

and

k=-5

so, since the center of the circle is at

(h,k)

substituting the values:

(6,-5) this are the coordinates of the center of the circle

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Keywords: Bisector, Line segment

Learn more about line segments at:

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