Question

a sample of air occupies 2.50 L at a temperature of 22.0c . what volume will this sample will this occupy inside a hot air baloon at a temperature of 43.0c assume that the pressure inside the balloon remains constant.

Answer 1

Answer:

The volume occupied by the air inside the hot balloon is 2.67 L.

Explanation:

Initial volume of the balloon =$V_1= 2.50 L$

Initial temperature of the air inside the balloon $T_1= 22.0 °C = 295 K$

Final volume of the balloon = $V_2$

Final temperature of the air inside the balloon =$T_2= 43.0 °C = 316 K$

Using Charles law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_2=\frac{V_1\times T_2}{T_1}=\frac{2.50 L\times 316 K}{295 K}=2.67 L$

The volume occupied by the air inside the hot balloon is 2.67 L.

Answer 2

V1/T1= V2/T2   V =volume T= temp (in kelvin unit) 

2.5/(22+273)=V2/(43+273)
V2=2.7L