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melamori03 [73]
3 years ago
12

If I have 2.5 moles of a gas at a pressure of 7.4 atm and volume of 8.2 liters. What is the temperature

Chemistry
1 answer:
frez [133]3 years ago
4 0

Answer:

295.78K

Explanation:

For this question you can use the ideal gas law, which is

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the ideal gas constant, and T is temperature.

We need to find temperature, so we need to rearrange the equation to solve for T

T=\frac{PV}{nR}

We are given n=2.5mol, P=7.4atm, and V=8.2L. We can use the gas constant R=.08206 to find the temperature in kelvin. To do so, plug all of the values into the equation (I'll be excluding units for simplicity)

T=\frac{(7.4)(8.2)}{(2.5)(.08206)} \\\\ T=295.78

The temperature is 295.78K. To find it in Celsius, subtract 273.

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Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer
jeyben [28]

Answer:

\rm Cl_2 + 2\; KBr \to Br_2 + 2\; KCl.

One chlorine molecule reacts with two formula units of (aqueous) potassium bromide to produce one bromine molecule and two formula units of (aqueous) potassium chloride.

Explanation:

<h3>Formula for each of the species</h3>

Start by finding the formula for each of the compound.

  • Both chlorine \rm Cl and bromine \rm Br are group 17 elements (halogens.) Each
  • On the other hand, potassium \rm K is a group 1 element (alkaline metal.) Each

Therefore, the ratio between \rm K atoms and \rm Br atoms in potassium bromide is supposed to be one-to-one. That corresponds to the empirical formula \rm KBr. Similarly, the ratio between

The formula for chlorine gas is \rm Cl_2, while the formula for bromine gas is \rm Br_2.

<h3>Balanced equation for the reaction</h3>

Write down the equation using these chemical formulas.

\rm ?\; Cl_2 + ?\; KBr \to ?\;Br_2 + ?\; KCl.

Start by assuming that the coefficient of compound with the largest number of elements is one. In this particular equation, both \rm KBr and \rm KCl features two elements each.

Assume that the coefficient of \rm KCl is one. Hence:

\rm ?\; Cl_2 + 1 \; KBr \to ?\;Br_2 + ?\; KCl.

Note that \rm KBr is the only source of \rm K and \rm Br atoms among the reactants of this reaction.

There would thus be one \rm K atom and one \rm Br atom on the reactant side of the equation.

Because atoms are conserved in a chemical equation, there should be the same number of \rm K and \rm Br atoms on the product side of the equation.

In this reaction, \rm Br_2 is the only product with \rm Br atoms.

One \rm Br atom would correspond to 0.5 units of \rm Br_2.

Similarly, in this reaction, \rm KCl is the only product with \rm K atoms.

One \rm K atom would correspond to one formula unit of \rm KCl.

Hence:

\displaystyle \rm ?\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl.

Similarly, there should be exactly one \rm Cl atom on either side of this equation. The coefficient of \rm Cl_2 should thus be 0.5. Hence:

\displaystyle \rm \frac{1}{2}\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl.

That does not meet the requirements, because two of these coefficients are not integers. Multiply all these coefficients by two (the least common multiple- LCM- of these two denominators) to obtain:

\displaystyle \rm 1\; Cl_2 + 2 \; KBr \to 1\;Br_2 + 2\; KCl.

7 0
3 years ago
PLS I WILL GIVE BRAINLY How do the number of violence electrons of the light metals compared to those heavier than boron
SCORPION-xisa [38]

The valence electron of the light metals are all in the range of 1 to 3.

<h3>What are Valence electron ?</h3>

Valence Electron is the number of electrons in the outer shell of an atom which participate in bond formation.

Number of Valence Electron in Boron is 3 and other light metals lighter than Boron have 1 , 2 of Lithium and Beryllium respectively,

The valence electron of the light metals are all in the range of 1 to 3.

To know more about Valence Electron

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4 0
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This is the process that cells reproduce and replace old or damaged cells.
Vedmedyk [2.9K]

Answer:

mitosis

Explanation:

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Alenkasestr [34]

Answer:

a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer

Explanation:

The lab apparatus that would be needed to prepare a solution of sodium chloride would be <em>a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer.</em>

The weighing balance would be used to weigh out the required amount of sodium chloride. The beaker or flask would be placed on the weighing balance and its weight zeroed. The spatula would then be sued to take out the sodium chloride from its container into the beaker till the required amount is reached. The measuring cylinder would then be used to measure out the required volume of water which would be added to the salt in the beaker. The stirrer would then be used to stir the mixture in order for the salt to dissolve.

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2 years ago
= 25 X 5 = (use the correct number of sig figs)
Anton [14]

Answer:

1.25 *10^2

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25*5 = 125

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