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melamori03 [73]
3 years ago
12

If I have 2.5 moles of a gas at a pressure of 7.4 atm and volume of 8.2 liters. What is the temperature

Chemistry
1 answer:
frez [133]3 years ago
4 0

Answer:

295.78K

Explanation:

For this question you can use the ideal gas law, which is

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the ideal gas constant, and T is temperature.

We need to find temperature, so we need to rearrange the equation to solve for T

T=\frac{PV}{nR}

We are given n=2.5mol, P=7.4atm, and V=8.2L. We can use the gas constant R=.08206 to find the temperature in kelvin. To do so, plug all of the values into the equation (I'll be excluding units for simplicity)

T=\frac{(7.4)(8.2)}{(2.5)(.08206)} \\\\ T=295.78

The temperature is 295.78K. To find it in Celsius, subtract 273.

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Read 2 more answers
Express the following in liters at STP:<br><br><br><br> 6.62 x 10-3 moles HF
serious [3.7K]

Answer:

The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L

Explanation:

Given data:

Number of moles of HF =  6.62×10⁻³ mol

Volume of HF in litter at STP = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Standard temperature = 273 K

Standard pressure = 1 atm

Now we will put the values in formula.

1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K

V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K  / 1 atm

V = 148.38×10⁻³ L

Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.

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3 years ago
What is the percent composition in chloric acid (HClO3)?
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