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melamori03 [73]
3 years ago
12

If I have 2.5 moles of a gas at a pressure of 7.4 atm and volume of 8.2 liters. What is the temperature

Chemistry
1 answer:
frez [133]3 years ago
4 0

Answer:

295.78K

Explanation:

For this question you can use the ideal gas law, which is

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the ideal gas constant, and T is temperature.

We need to find temperature, so we need to rearrange the equation to solve for T

T=\frac{PV}{nR}

We are given n=2.5mol, P=7.4atm, and V=8.2L. We can use the gas constant R=.08206 to find the temperature in kelvin. To do so, plug all of the values into the equation (I'll be excluding units for simplicity)

T=\frac{(7.4)(8.2)}{(2.5)(.08206)} \\\\ T=295.78

The temperature is 295.78K. To find it in Celsius, subtract 273.

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Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)

First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)

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Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

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Answer:

The energy transferred between samples of matter because of a difference in their temperatures is called a. heat.

Explanation:

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