If I have 2.5 moles of a gas at a pressure of 7.4 atm and volume of 8.2 liters. What is the temperature
1 answer:
Answer:
295.78K
Explanation:
For this question you can use the ideal gas law, which is
where P is pressure, V is volume, n is moles of substance, R is the ideal gas constant, and T is temperature.
We need to find temperature, so we need to rearrange the equation to solve for T
We are given n=2.5mol, P=7.4atm, and V=8.2L. We can use the gas constant R=.08206 to find the temperature in kelvin. To do so, plug all of the values into the equation (I'll be excluding units for simplicity)
The temperature is 295.78K. To find it in Celsius, subtract 273.
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Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
<h3>Definition of mole fraction</h3>The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
In this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
Solving:
<u><em>Mole fraction O₂ = 0.434</em></u>
Finally, the mole fraction of O₂ in the mixture is 0.434.
Learn more about mole fraction:
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