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3 years ago

What are the steps to simplify 1/x⁻︎¹

Mathematics

1 answer:

andriy [413]3 years ago

6 0

Move $x^{-1}$ up to the numerator

$\frac{1}{x^{-1}} = \frac{1 \cdot x^1}{1} = \frac{x}{1} = x$

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PLEASE ANSWER THIS QUESTION CORRECTLY, I’LL GIVE YOU BRANLIEST! Please answer my other math questions if you do solve this one,

kirill [66]

Answer: It's true.

Step-by-step explanation:

3 0

3 years ago

How do you solve this?

dangina [55]

Note that 125 = 5³. Make use of the factorization of the sum of cubes:

a³ +b³ = (a+b)(a² -ab +b²) . . . . . . a formula worth keeping handy

Then ...

$\dfrac{x^3+5^3}{x+5}=\dfrac{(x+5)(x^2-5x+5^2)}{x+5}=x^2-5x+25$

_____

When x=-5, this evaluates to

... (-5)²-5(-5) +25 = 75

7 0

3 years ago

Read 2 more answers

HELP HELP HELP HELP HELP HELP HELP

Strike441 [17]

Answer:

Hi,

In a square, all sides are equal.

The area is obtained by multiplying one side by another side.

So, A = L^2

A = Area

L = length of a side

24ft^2 = L^2

L = square root(24) = 4.9

L = 4.9

We can say x^2 = 24

And the length of one side is therefore 4.9

8 0

3 years ago

The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?

Alexxx [7]

Answer:

Perimeter = 22.809836694575

Step-by-step explanation:

A(-2, 2) ; B(6,2) ; C(0, 8)

$AB=\sqrt{\left( 6--2\right)^{2} +\left(2-2 \right)^{2} } =\sqrt{64} =8$

$AC=\sqrt{\left( 0--2\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{40} =2\sqrt{10}$

$BC=\sqrt{\left( 0-6\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{72} =6\sqrt{2}$

Then

The perimeter of ΔABC = AB + BC + AC

$=8+6\sqrt{2} +2\sqrt{10}$

= 22.809836694575

3 0

3 years ago

What is 2x-(x-2)=-2-(x-1)

bezimeni [28]

Distribute first so
2x-x+2=2-x+1
Combine like terms so
x+2=3-x
Get terms on the same side so
2x+2=3
Subtract 2
2x=1
Divide
X=1/2 or .5

8 0

4 years ago