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Nastasia [14]
3 years ago
5

Let X and Y be random variables with the following joint moment generating function: M_{X,Y}(s,t)=0.1+0.2e^s+0.3e^t+0.4e^{s+t}

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

We obtain the joint PMF directly from the joint MGF:

M_{X,Y}(s,t)=0.1+0.2e^s+0.3e^t+0.4e^{s+t}

\implies\mathrm{Pr}[X=x,Y=y]=\begin{cases}0.1&\text{for }x=y=0\\0.2&\text{for }x=1,y=0\\0.3&\text{for }x=0,y=1\\0.4&\text{for }x=y=1\\0&\text{otherwise}\end{cases}

Then

\mathrm{Pr}[X=Y]=\mathrm{Pr}[X=Y=0]+\mathrm{Pr}[X=Y=1]=0.1+0.4=\boxed{0.5}

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3 years ago
The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard form below.
elena-14-01-66 [18.8K]
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Read 2 more answers
If x-y =8 find the value of y when x=3
DedPeter [7]
Answer: y = -5

Substitute in 3 for x.
x - y = 8                            Substitution
3 - y = 8                            Subtract 3 from both sides
-y = 5                                Divide by -1 to both sides
y = -5                                Answer!

You can also check your work.
x - y = 8       
3 - (-5) = 8                  
3 + 5 = 8                        
8 = 8                                

8 0
3 years ago
The weight of a beg of pears at the local market averages 8 pounds with a standard deviation of 0.5 pound. The weight of all the
Blababa [14]
Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds

We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.

We have to convert x = 8.25 to z scores, which will be:

z= \frac{x-u}{s}= \frac{8.25-8}{0.5}

z score = 0.5

From the z table, the probability of z score being greater than 0.5 is 0.3085

Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085

Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
4 0
3 years ago
Solve for x<br> (x/r)+(x/w)+(x/t)= 1
MissTica

<em>x</em>/<em>r</em> + <em>x</em>/<em>w</em> + <em>x</em>/<em>t</em> = 1

<em>x</em> (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) = 1

<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>)

To make the solution a bit cleaner, multiply through the numerator and denominator by the LCM of each fraction's denominator, <em>rwt</em> :

<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) • <em>rwt</em> / <em>rwt</em>

<em>x</em> = <em>rwt</em> / (<em>rwt</em>/<em>r</em> + <em>rwt</em>/<em>w</em> + <em>rwt</em>/<em>t</em>)

<em>x</em> = <em>rwt</em> / (<em>wt</em> + <em>rt</em> + <em>rw</em>)

5 0
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