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yawa3891 [41]
3 years ago
9

Ryan and Marie had some marbles. if Ryan lost `15 marbles, he would have 4 times as many marbles as Marie. If Ryan lost 75 marbl

es,, he would have 11/2 times as many marbles as Marie. How many marbles did Ryan have at first?
Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0
Ryan's marbles   =  x
Marie has 4 times less marbles then Ryan would have if he lost 15 marbles (it means he would have x-15)
So, Marie marbles  =  (x-15):4
If Ryan lost 75 marbles (it means he would have x-75), he would have 1 1/2 times as many marbles as Marie.

We got an equation:                                  x-75=1\frac{1}2\cdot\frac{x-15}{4}

                                                                  x-75=\frac{3}2\cdot\frac{x-15}{4}

Multiply both sides by 8:                            8x-8\cdot75=3\cdot(x-15)

                                                                  8x-600=3x-45

Add 600 and subtract 3x on both sides:    5x=555

Divide both sides by 5:                               x=111


Answer:    Ryan have 111 marbles.

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