1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sliva [168]
3 years ago
14

40 points!!!

Mathematics
2 answers:
Setler79 [48]3 years ago
6 0

Answer:

option a is the answer

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

Karolina [17]3 years ago
3 0
I think it would be the first
You might be interested in
consider the graph of the following qudratic equation. y= -x^2 -10x + 24.What is the y-value of the vertex?
3241004551 [841]

Given that the quadratic equation is y=-x^{2}-10 x+24

We need to determine the y - value of the vertex.

<u>The x - value of the vertex:</u>

The x - value of the vertex can be determined using the formula,

x=-\frac{b}{2 a}

where a=-1, b=-10, c=24

Substituting these values, we get;

x=-\frac{(-10)}{2(-1)}

Simplifying the terms, we get;

x=-\frac{-10}{-2}

x=-5

Thus, the x - value of the vertex is -5.

<u>The y - value of the vertex:</u>

The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation y=-x^{2}-10 x+24

Thus, we get;

y=-(-5)^{2}-10(-5)+24

Simplifying the values, we have;

y=-25+50+24

y=49

Thus, the y - value of the vertex is 49.

8 0
3 years ago
Question in attachment
kiruha [24]

Answer:

1. a= 7, A = 49 degrees

Side A = 7 , Side B = 24, Side C = 25

A= 49 degrees, C = 90 degrees , B=41

2. A= 4, B = 6.9, C=8

A= 22 degrees, B = 68, C= 90

3. A= 7, B = 14.4, C=16

A= 45 , B=45  , C=90

6 0
3 years ago
Graphing Exponential Functions In Exercise, sketch the graph of the function.
denis23 [38]

Answer:

The graph of the function f(x) = (1/2)^2x + 4 is attached as image below.

Analysis:

We have two intersection points in the graph

The function f(x) = (1/2)^2x + 4  intersects the y-axis at points (0,4)

The function f(x) = (1/2)^2x + 4  intersects the x-axis at points (-16,0)

f(x) is positive for x>-`16

f(x) is negative for x<-`16

5 0
3 years ago
Rewrite 128 in an expomential notion using 2 as a base
KiRa [710]
\underbrace{2\times 2\times 2\times 2\times 2\times 2 \times 2} = 128\\\\~~~~~~~~~~~~~~~~~7\\\\\\\boxed{\bf{2^7 =128}}}
3 0
3 years ago
Tracy needs to find the length and width of the equipment room where she works. The room is 2 meters longer than it is wide. The
Alekssandra [29.7K]

Answer:

The answer to your question is: width = 3 meters

Step-by-step explanation:

Data

Perimeter = 16 meters

The room is 2 meters longer than its width, then   length = width + 2

Perimeter = 2 length + 2 width

   16 =  2(width + 2) + 2 width

    16 = 2 width + 4 + 2 width

   16 = 4 width +4

   16 - 4 = 4 width

    12 = 4 width

    12/4 = width

     3 = width  

length = 3 + 2 = 5 meters

8 0
3 years ago
Other questions:
  • Julio bought 3/5 pound of potato salad for dinner.Wilma bought 5/4 the amount of potato salad that Julio did.How much potato sal
    15·1 answer
  • 7x+9≥2
    13·1 answer
  • Write the expression 12^-2 in simplest form.
    5·1 answer
  • João comprou uma TV por R$ 2 400,00; um celular por R$ 1 325,00 e um tênis por R$ 130,00, qual o valor total da compra?
    5·1 answer
  • A jacket used to cost $54. After a 40% discount, what is the new cost of the jacket?
    12·1 answer
  • The cost of a shirt was originally $ 40 but the price dropped to $32 because it was on sale. What was the percent change in the
    14·2 answers
  • Please Help and write the equation down as well!!<br> I´ll mark whoever is right Brainiest!
    15·1 answer
  • Factor the denominator of the rational function y= 2x/x^2-16
    5·1 answer
  • The leg of an isosceles triangle has a length 2x+4 and the base has length 3x. The
    9·1 answer
  • In the problem 3/4 • N=1, n must be
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!