The answer is c
1/6 divided by 1/2
i had this question on my own
Solution: Any value for a variable that makes the equation true.
Reciprocal: Focuses on the use of multiplication and division
Coefficient: A number that is multiplied by a variable in an algebraic expression is a coefficient
Term: A term of an algebraic expression is a number, variable, or product of numbers and variables
Base: The base of a power is the factor that is multiplied repeatedly in the power.
Hope this helps, and have a great day!
Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
Well, you could assign a letter to each piece of luggage like so...
A, B, C, D, E, F, G
What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.
My answer and workings are below...
35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.
210 arrangements (35 x 6) when order is taken into consideration.
*There are 6 ways to configure 3 letters.
Alternative way to solve the problem...
Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.