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Burka [1]
2 years ago
5

I will give brainliest

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Answer: she was not correct, she messed up the equation.

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How do you solve this algebreically?<br> 3/8=x/20
Llana [10]

Answer:

7.5

Step-by-step explanation:

3/8 = x/20

3(20) = 8x

8x = 60

x = 60/8

x = 7.5

6 0
3 years ago
Given the midpoint and one endpoint of a line segment, find the other endpoint.
lozanna [386]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{\frac{5}{8}}~,~\stackrel{y_1}{\frac{27}{8}})\qquad  (\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right) \\\\\\ \left( \cfrac{x+\frac{5}{8}}{2}~~,~~\cfrac{y+\frac{27}{8}}{2} \right)=\stackrel{midpoint}{\left( -\frac{7}{6}~~,~~-\frac{10}{3} \right)}

\bf -------------------------------\\\\ \cfrac{x+\frac{5}{8}}{2}=-\cfrac{7}{6}\implies  x+\cfrac{5}{8}=-\cfrac{14}{6}\implies x=-\cfrac{14}{6}-\cfrac{5}{8} \\\\\\ x=\cfrac{-14(4)-5(3)}{24}\implies x=\cfrac{-56-15}{24}\implies \boxed{x=-\cfrac{71}{24}}\\\\ -------------------------------\\\\ \cfrac{y+\frac{27}{8}}{2}=-\cfrac{10}{3}\implies y+\cfrac{27}{8}=-\cfrac{20}{3}\implies y=-\cfrac{20}{3}-\cfrac{27}{8} \\\\\\ y=\cfrac{-20(8)-27(3)}{24}\implies y=\cfrac{-160-81}{24}\implies \boxed{y=-\cfrac{241}{24}}

3 0
3 years ago
A drawing of a basketball backboard was made using semicircle and rectangle
elena-14-01-66 [18.8K]
Answer:B 253.17
100% sure
8 0
2 years ago
Without solving determine the number of real solutions for each quadratic equation
seropon [69]

Answer:

b^2-4b+3=0

b²-3x-b+3=0

b(b-3)-1(b-3)=0

(b-3)(b-1)=0

either

b=3 or b=1

.

2n^2 + 7 = -4n + 5

2n²+4n+7-5=0

2n²+4n+2=0

2(n²+2n+1)=0

(n+1)²=0/2

:.n=-1

.

x - 3x^2 = 5+ 2x - x^2

0=5+ 2x - x^2-x +3x^2

0=5+x+2x²

2x²+x+5=0

comparing above equation with ax²+bx +c we get

a=2

b=1

c=5

x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1

={-1±√-39}/2

3 0
2 years ago
Geometry:
Eddi Din [679]

Answer:

<AEB = obtuse angle

<AED = straight angle

<BEA = obtuse angle

<BEC = straight angle

<CDE = not angle

<CEA = acute angle

<DEA = straight angle

<DEB = acute angle

<DEC = obtuse angle

Step-by-step explanation:

3 0
2 years ago
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