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3 years ago

The boxplot displays the scores from an economics chapter test. identify the second quartile.

Mathematics

2 answers:

netineya [11]3 years ago

5 0

Answer:

Step-by-step explanation:

The middle line is the median, then from left to right the lines are the first, second, third and fourth quartile.

Oksana_A [137]3 years ago

5 0

Answer:

Option C) 80 is the median score.

Step-by-step explanation:

We are given the following information :

The second quartile also known as the median of the data divides the range in the middle and has 50 percent of the data below it that is divided the data into two equal parts.
A box and whisker plot also known as box plot tells the five-number summary of a set of data.
The five-number summary is the minimum, first quartile, median, third quartile, and maximum of the data set.
In a box plot, a box is drawn from the first quartile to the third quartile. A vertical line in the box represents the median of data.

In the given box plot:

The end point of box represents the first and the third quartile. The line in the box is the median of data set.

Hence, the second quartile or median is 80.

Option C) 80 is the median score.

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Monica spent 3/4 hours listening to tapes of Beethoven and Brahms. She spent 1/5 hours listening to Beethoven . How many hours w

ELEN [110]

Answer:

Monica spent 0.55 hours listening to Brahms.

Step-by-step explanation:

We are given the following in the question:

Amount of time spent listening to tapes of Beethoven and Brahms =

$=\dfrac{3}{4}$

Amount of time spent listening to Beethoven =

$=\dfrac{1}{5}$

Total time spent listening to Brahms =

Amount of time spent listening to tapes of Beethoven and Brahms - Amount of time spent listening to Beethoven

$=\dfrac{3}{4}-\dfrac{1}{5}\\\\=\dfrac{15-4}{20}\\\\=\dfrac{11}{20}\text{ Hours}\\\\=0.55\text{ Hours}$

Thus, Monica spent $\frac{11}{20}\text{ hours}$ listening to Brahms.

7 0

3 years ago

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Am solving this problem correct

cestrela7 [59]

A) The degree of the first term is... 1
$first \ term = 3t$
The degree of the second term is... 2
$second \ term = t^2$
The degree of the third term is... 4
$third \ term = t^4$

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4

6 0

3 years ago

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Hi :) how to do question 7 ?

Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
After simplyfying the expressions we get finally : -12+8x-8y=0
now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16