Answer:
The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.
333 - 257 = 76 have spills.
This means that
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).
I think it would be y=10x+2
Answer: 0.04 meters
Step-by-step explanation:
Convert cm to meters by dividing the length by 100.
4/100= = 0.04
Answer:
1500
Step-by-step explanation:
2500/5=500,*3=1500
Answer:
The inverse is ±sqrt(100-x)
Step-by-step explanation:
y= 100 - x^2
Exchange x and y
x = 100 -y^2
Solve for y
Subtract 100 from each side
x-100 = 100-100-y^2
x-100 = - y^2
Multiply by -1
-x+100 = y^2
100 -x = y^2
Take the square root of each side
±sqrt(100-x) = sqrt(y^2)
±sqrt(100-x) = y
The inverse is ±sqrt(100-x)