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3 years ago

What is the distance of work 1 2/3 and 1 1/4

2 answers:

8 0

The distance is 5/12 because when i changed the denominator into 12 and multiplied the top by 3 and 4 then subtracted and got 5/12

PIT_PIT [208]3 years ago

5 0

$1\dfrac{2}{3}-1\dfrac{1}{4}=1\dfrac{2\cdot4}{3\cdot4}-1\dfrac{1\cdot3}{4\cdot3}=1\dfrac{8}{12}-1\dfrac{3}{12}=\dfrac{8-3}{12}=\boxed{\frac{5}{12}}$

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A student attempted to generate an equivalent expression using the distributive property, as shown below:

Schach [20]

It is 6 was not multiplied by 3
The answer should be 6(m+3)= 6m+ 18

5 0

4 years ago

Read 2 more answers

Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b

jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .

So; as each place is fitted with either 0 or 1

$\mathbf{|R|= 2^{10}}$

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

$\mathbf{P(E) = \dfrac{|E|}{|R|}}$

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

$\mathbf{{|E|}=1 }$ ; $\mathbf{|R|= 2^{10}}$

$\mathbf{P(E) = \dfrac{1}{2^{10}}}$

4 0

3 years ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

Dianna and Becky were playing on the same soccer team and took turns being goalie. They stoped 9 out of 10 shots made against th

vitfil [10]

Answer:

27 balls

Step-by-step explanation:

If Dianna and Becky stopped 9 out of 10 shots made against them.

It means they allowed in 1 out of 10 shots made against them.

This is best solved using ratios

Proportion of Shots Stopped : Proportion of Shots allowed=9:1

If the other team scores 3 points, it means the number of shots allowed =3