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Mashutka [201]
3 years ago
15

What is the distance of work 1 2/3 and 1 1/4

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
The distance is 5/12 because when i changed the denominator into 12 and multiplied the top by 3 and 4 then subtracted and got 5/12
PIT_PIT [208]3 years ago
5 0
1\dfrac{2}{3}-1\dfrac{1}{4}=1\dfrac{2\cdot4}{3\cdot4}-1\dfrac{1\cdot3}{4\cdot3}=1\dfrac{8}{12}-1\dfrac{3}{12}=\dfrac{8-3}{12}=\boxed{\frac{5}{12}}
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Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose
spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The home team therefore wins 50% of its games

This means that p = 0.5

Determine the probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Sample of 80 means that n = 80 and, by the Central Limit Theorem:

\mu = p = 0.65

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.65 - 0.5}{0.0559}

Z = 2.68

Z = 2.68 has a pvalue of 0.9963

1 - 0.9963 = 0.0037

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

7 0
2 years ago
How can you use the side lengths of a triangle to determine if it is an acute triangle?
lozanna [386]
The smaller the length u can figure out and if u can't put a small square in the cornorn
3 0
3 years ago
I need help ! <br> <img src="https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D%20%2B5%5Csqrt%7B15%7D" id="TexFormula1" title="3\sqrt{5} +5
Feliz [49]

Answer:

26

Step-by-step explanation:

SORRY IF IM WRONG

6 0
2 years ago
Two parts Someone please help!!!!!
aivan3 [116]

Answer:

Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x

Part two: The area of the rectangle is 8 feet² when its width is 2 feet

Step-by-step explanation:

Assume that the width of the rectangle is x

∵ The width of the rectangle = x feet

∵ The length of the rectangle is 2 ft less than three times its width

→ That means multiply the width by 3, then subtract 2 from the product

∴ The length of the rectangle = 3(x) - 2

∴ The length of the rectangle = (3x - 2) feet

∵ The area of the rectangle = length × width

∴ A(x) = (3x - 2) × x

→ Multiply each term in the bracket by x

∵ A(x) = x(3x) - x(2)

∴ A(x) = 3x² - 2x

∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x

∵ The rectangle has a width of 2 ft

∵ The width = x

∴ x = 2

→ Substitute x by 2 in A(x)

∵ A(2) = 3(2)² - 2(2)

∴ A(2) = 3(4) - 4

∴ A(2) = 12 - 4

∴ A(2) = 8

∴ The area of the rectangle is 8 feet² when its width is 2 feet

5 0
3 years ago
PLZ HELP WILL REWARD!!!!!!!!!!!!!!
iragen [17]

an equation would be 95d=475

5 0
3 years ago
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