Question

The value of computer decreases with its age until it is worth nothing a computer that was purchases new for 0 years is worth 2220 1540 after 6 years problem whats the value after 8 years and what is the linear function V(x)

Answer 1

Answer:

$V(x) = -\frac{340}{3}x +2220$

$V(8) = 1313.3$

Step-by-step explanation:

Given

Let x represent years and V represents the value.

So, we have:

$(x_1,v_1) = (0,2220)$

$(x_2,v_2) = (6,1540)$

Solving (a): The linear function

First, we calculate the slope (m)

$m = \frac{v_2 - v_1}{x_2 - x_1}$

This gives:

$m = \frac{1540-2220}{6-0}$

$m = \frac{-680}{6}$

$m = -\frac{340}{3}$

The linear function is calculated using:

$v - v_2 = m(x - x_2)$

Where:

$(x_2,v_2) = (6,1540)$

$m = -\frac{340}{3}$

So, we have:

$v - 1540 = -\frac{340}{3}(x - 6)$

Open bracket

$v - 1540 = -\frac{340}{3}x +\frac{340}{3}* 6$

$v - 1540 = -\frac{340}{3}x +680$

Make v the subject

$v = -\frac{340}{3}x +680+1540$

$v = -\frac{340}{3}x +2220$

So, the function is:

$V(x) = -\frac{340}{3}x +2220$

Solving (b): When x = 8

Substitute 8 for x in $V(x) = -\frac{340}{3}x +2220$

$V(8) = -\frac{340}{3}*8 +2220$

$V(8) = -\frac{340*8}{3} +2220$

$V(8) = -\frac{2720}{3} +2220$

Take LCM

$V(8) = \frac{-2720+2220*3}{3}$

$V(8) = \frac{-2720+6660}{3}$

$V(8) = \frac{3940}{3}$

$V(8) = 1313.3$

Hence, its value after 8 years is 1313.3