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ira [324]
3 years ago
7

Determine two pairs of polar coordinates for the point (4, -4) with 0° ≤ θ < 360°.

Mathematics
2 answers:
grin007 [14]3 years ago
7 0
(4√2, 225°), (-4√2, 45°)
KatRina [158]3 years ago
4 0

The point (4, -4) lies in Quadrant IV. Since we are interested only in positive angles, we choose 315 degrees with a radius (magnitude) of 4√2. That automatically eliminates Answer Choices A, B and C, so all we have to do now is to verify that (-4√2, 135 degrees) also represents (4, -4). It does: Going to Quadrant II with angle 135 degrees, and then using -4√2 as the magnitude, takes us to Quadrant IV.

Thus, D is the correct answer.

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Find the regular price. Round to the nearest cent . Sales price is 56.78 percent discount is 40%
LenaWriter [7]

100\%-40\%=60\%\\60\% = \frac{60}{100}=\frac{6}{10}=\frac{3}{5}\\\\

Numerator is 3 and denominator is 5. So, we divide the sales price by 3 and we multiply by 5 to get the whole fraction, or 100%.

\frac{56.78*5}{3} \\\frac{283.9}{3} \\94.6333333333333...

Your regular price sounds recurring, so you might have made a mistake copying.

The answer for what you've got is 94.633333...

5 0
3 years ago
Please help, my calculator isn't working and I need to go to the hospital soon. if possible could someone please give the answer
Goshia [24]
A) 500 ml
b) 8.5 km
c) 480 cm
d) 9000 g
e) 550 mm
4 0
3 years ago
(x-3)(2x+1) Can someone help me on this please
a_sh-v [17]
2x^2-5x-3

This is the answer I believe, I apologize if it’s incorrect
6 0
3 years ago
HELP!! Simplify the expression 3y^2 • 4x^2y • 5x Using the laws of exponents. Show each step of your work.
JulsSmile [24]
<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3


</span>where ((<span>y^2 * y)) adding the powers in case of multiplication

and also for this:</span><span> (<span>x^2*x)</span>  </span>
5 0
4 years ago
Write an expression equivalent to h^6/h^3 in the form of h^m
Pavel [41]

Answer:

h^3 = h^m

Step-by-step explanation:

\frac{h^6}{h^3} = h^m

6 - 3 = 3

keep the base same, therefore

h^3 = h^m

Hope this helps!

3 0
3 years ago
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