Question

What are the values of the coefficients and constant term of 0=4-7x^2+x in standard form?

Answer 1

Answer:

$a=-7\\b=1\\c=4$

Step-by-step explanation:

The standard form of a quadratic equation has the following formula:

$ax^2 +bx+c=0$

Where a  and b are the coefficients that accompany the term x² and x and c is the constant term.

In this case we have the following equation:

$0=4-7x^2+x$

We can rewrite the equation in the following way

$-7x^2+x+4=0$

Then you can see that the values for the coefficients  and constant term are:

$a=-7\\b=1\\c=4$

Answer 2

For this case we have that by definition, a quadratic equation is of the form:

$ax ^ 2 + bx + c = 0$

Where:

$ax ^ 2$: It is the quadratic term

bx: It is the linear term

c: It is the independent term

So, if we have the following expression:

$0 = 4-7x ^ 2 + x$

We rearrange:

$-7x ^ 2 + x + 4 = 0$

We have to:

-7: It is the quadratic coefficient

1: It is the linear coefficient

4: It is the independent term

ANswer:

-7: It is the quadratic coefficient

1: It is the linear coefficient

4: It is the independent term