Answer:
3.7 m
Explanation:
ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky
The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of
t = √ (2h/g) = √(2(15)/9.8) = 1.75 s
Without the tail wind, the ball travels horizontally
d = vt = 68(1.75) = 119 m
The tailwind exerts a constant acceleration on the ball of
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s
so the distance with tailwind is
d = v(avg)t = 70.1(1.75) = 122.675 m
The extra distance is 122.675 - 119 = 3.675 = 3.7 m
Answer:
20 m/s
Explanation:
Height (s)= 20m
acceleration (a) = 10 m/s^2
v=?
we know,
V^2= U^2 + 2as. (U is initial velocity)
or,. V^2 = 0 + 2 × 10 × 20
or, V^2 = 400
or,. V = 20 m/s
The components of the resultant will be: (18, 12)
In order to find the magnitude you have to apply the Pythagorean theorem:
√(18² + 12²) = √468 = 21.6
Therefore, the magnitude of the resultant vector is 21.6
The direction is given by the formula:
α = tan⁻¹(v_y / v_x)
= <span>tan⁻¹(12/18)
= 33.7°
Therefore, the direction will be 33.7° from the x-axis.</span>
Answer:
Fossil fuels have been used for centuries to generate power, but there are many disadvantages associated with their use:
Fossil fuels pollute the environment.
Fossil fuels are non-renewable and unsustainable.
Drilling for fossil fuels is a dangerous process.
Explanation:
can you help me please? brainly.com/question/21745542
Explanation:
The Net Force of the object can be written by:
Fnet = ma
where m is the mass of the object in <em>kg</em>
a is the acceleration of the object in <em>m/s^2</em>
Hence by applying the formula we get:
Fnet = (2.0)(3.0)
= 6N
We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:
Fnet = Pushing Force + (-Friction)
6N = 6N - Friction
Friction = 0N
Hence the<u> </u><u>f</u><u>orce of friction is 0N.</u>
