Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10
^- 8 N how far apart are centers of mass?
1 answer:
Answer:
Explanation:
The formula for this is
where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.
Filling in:
and moving things around to solve for r:
Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m
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Answer:
Distance = 30m
Displacement = 6m W
Explanation:
Given the following:
Movement 1 = 18m W
Movement 2 = 12m E
Diatance is a scalar quantity with only magnitude and no direction. That is, in Calculating the distance moved by the locomotive, the direction of travel or movement of the object is not considered. It only measures the total amount of movement made during the Time of motion.
Therefore, total distance traveled equals :
Movement 1 + movement 2
18m + 12m = 30m
B) Displacement also measures the movement made by an object. However, Displacement is a vector quantity and therefore, considers both magnitude and direction of travel of the object. Therefore, it measures the overall change in position of the object from its starting position.
Therefore, Displacement of the locomotive equals:
18m W - 12m E = 6m E
Answer:
Pressure,
Explanation:
It is given that,
Combined mass of the man and the chair, m = 95 kg
Radius of the leg of chair, r = 0.5 cm = 0.005 m
A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.
Area of 4 legs, A = 4 A
So, the pressure each leg exert on the floor is . Hence, this is the required solution.