Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10
^- 8 N how far apart are centers of mass?
1 answer:
Answer:
Explanation:
The formula for this is
where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.
Filling in:
and moving things around to solve for r:
Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m
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Force of 500 N is acting on the parachutist.
Parachutist applies 500 N force in downward direction.
Answer:
300 N upward
Solution:
Parachutist feels air resistance of 800 N.
Thus, 800 N of force is acting in upward direction.
Total force acting on the parachutist is given by,
= air resistance force - force of parachutist
= 800-500
= 300 N
Direction of force is in upward direction because the air resistance force is more than force of parachutist.
Answer:
The initial velocity is 0.5114 m/s or 511.4 mm/s
Explanation:
Let the initial velocity be 'v'.
Given:
Mass of the ball (m) = 130 g = 0.130 kg [ 1 g = 0.001 kg]
Initial height of the ball (h₁) = 1.4 mm = 0.0014 m [ 1 mm = 0.001 m]
Final height of the ball (h₂) = 15 mm = 0.015 m
Now, from conservation of energy principle, energy can neither be created nor be destroyed but converted from one form to another.
Here, the kinetic energy of the ball is converted to gravitational potential energy of the ball after reaching the final height.
Change in kinetic energy is given as:
As it just touches the 15 mm high roof, the final velocity will be zero. So,
.
Now, the change in kinetic energy is equal to:
Change in gravitational potential energy = Final PE - Initial PE
So,
[ g = 9.8 m/s²]
Now, Change in KE = Change in PE
Therefore, the initial velocity is 0.5114 m/s or 511.4 mm/s