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chubhunter [2.5K]
3 years ago
8

What is fluorine sidekicks

Physics
1 answer:
Talja [164]3 years ago
6 0

Fluorine is the most reactive and the most electronegative of all the elements. Fluorine is a pale yellow, diatomic, highly corrosive, flammable gas, with a pungent odor. It is the lightest halogen.

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What's a Blackhole ?​
Vlad1618 [11]

Answer:

A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.

7 0
3 years ago
Water rushes down a river with a velocity of 2.4 m/s. Four seconds after leaving the rapids the velocity of the water has decrea
Crazy boy [7]
A=(v2-v1)/t
v2=0,6m/s
v1=2,4m/s
t=4s
a=(0,6-2,4)/4=-1,8/4=-0,45 m/s^2
8 0
3 years ago
A 1,200 kg subcompact car accelerates at a rate of 3.0m/s
ludmilkaskok [199]
Missing question (found on internet): 
"what is the force of the car?"

Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
F=ma
For the car in the problem,
m=1200 kg
a=3.0 m/s^2
So the force that accelerates the car is
F=(1200 kg)(3.0 m/s^2)=3600 N
6 0
3 years ago
Help me, please!!!!!!
igomit [66]

Answer:

Explanation:

The highest surface part of a wave is called the crest, and the lowest part is the trough. The vertical distance between the crest and the trough is the wave height. The horizontal distance between two adjacent crests or troughs is known as the wavelength...

6 0
3 years ago
Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will
denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

                 W_{net} = \Delta K

Also,   \Delta K = K_{initial} - K_{final}

                        = (0 - 4.0 \times 10^{-17}) J

                        = -4.0 \times 10^{-17} J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

                w = -Fd

       -4.0 \times 10^{-17} J = -F \times 0.3 m

                F = 1.33 \times 10^{-16}  

Therefore, relation between electric field and force is as follows.

              E = \frac{F}{q}

                 = \frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}

                 = 0.831 \times 10^{3} C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is 0.831 \times 10^{3} C.

3 0
4 years ago
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