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alex41 [277]
3 years ago
14

When find the margin error for the mean of a normally distributed population from a sample what is the critical probability assu

ming a confidence level of 58%
Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0

Answer:

0.21

Step-by-step explanation:

UNO [17]3 years ago
5 0
<span>( 1 - .58)/2 = .21 HERES THE ANSWER 

</span>
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2 2/5 in kilometers in 3 3/4 minutes unit rate
Mars2501 [29]

Answer:

Step-by-step explanation:

d = r * t     Divide both sides by t

r = d / t

d = distance = 2.25 km

t = time = 3 3/4 minutes = 3.75 minutes

r = 2.25 / 3.75

r = 0.6 km / minute

r = 3/5 km / minute

If the units are different than those given, please state them underneath my answer. I'll get to it as soon as I see your comment.

5 0
2 years ago
What is this Find the value of |-6| - 3(42 - 1).
Artist 52 [7]

Answer:

-117

Step-by-step explanation:

So, basically all you have to do is use the absolute values in order to use order of operations and simplify it along with the multiplied grouping.

Hope this helps :)

5 0
3 years ago
Please answer it’s only one question please fast I really need it please show work
Scilla [17]

Answer:

Yes answer is c) 4

In 1st cube 6-4=2

In 2nd cube 9-8=1

In 3rd cube 4-1=3

5 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Molodets [167]
Add the following polynomials:
All polynomials are already ordered according to their degree (exponent), and therefore you can just add straight down in columns.
For x3: 2 + 1 - 3 = 0
For x2: -4 + 6 + 2 = 4 
For x: 6 - 8 -4 = -6
Constants: -3 + 12 - 7 = 2

The answer is:
4x^2 - 6x + 2
6 0
3 years ago
The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th
Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ)  of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19

Then the probability is given as

\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

To know more about Probability

brainly.com/question/11234923

#SPJ1

3 0
2 years ago
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