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Svetradugi [14.3K]
2 years ago
14

What multiplies to negative 24 and adds to 2

Mathematics
1 answer:
exis [7]2 years ago
7 0
Let us assume the two numbers to be "x" and "y".
Then
xy = - 24
x = - (24/y)
And
x + y = 2
Putting the value of x from the first equation in the second equation, we get
x + y = 2
- (24/y) + y = 2
- 24 + y^2 = 2y
y^2 - 2y - 24 = 0
y^2 - 6y + 4y - 24 = 0
y(y - 6) + 4(y - 6) = 0
(y - 6) (y + 4) = 0
When
y - 6 = 0
y = 6
Then
x + y = 2
x + 6 = 2
x = 2 - 6
   = -4
And when
y + 4 = 0
y = -4
Then
x + y = 2
x - 4 = 2
x = 2 + 4
   = 6
So the two unknown numbers are -4 and 6.
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joja [24]
The answer is (1, -2)

because f(x) = y

so, where y is -2 , x is 1
8 0
3 years ago
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Simplify x+4/2 - x-5/7
strojnjashka [21]

Answer:

(5 - x)/7 + (x + 4)/2

not rly a simlification but it changes it?

Hope This Helps!!!

4 0
2 years ago
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At a high school basketball game the Lions and the Eagles are playing. The Lions attempted 18 free throws and made 10, attempted
rodikova [14]

Answer:

(a) 55.6%

(b) 45.0%

(c) 38.5%

(d) 27.1%

(e) 64

(f) 47

(g) The Lions

Step-by-step explanation:

(a) Free throw % for Lions is

\dfrac{10}{18}\times 100\% = 55.6\%

(b) Free throw % for Eagles is

\dfrac{9}{20}\times100\% = 45\%

(c) For the Lions, they attempted a total of 51 + 14 = 65 field goals and made 21 + 4 = 25.

Field goal % for Lions is

\dfrac{25}{65}\times100\% = 38.5\%

(d) For the Eagles, they attempted a total of 45 + 14 = 59 field goals and made 10 + 6 = 16.

Field goal % for Eagles is

\dfrac{16}{59}\times100\% = 27.1\%

(e) Total points by Lions = (10 × 1) + (21 × 2) + (4 × 3) = 10 + 42 + 12 = 64

(f) Total points by Eagles = (9 × 1) + (10 × 2) + (6 × 3) = 9 + 20 + 18 = 47

(g) The Lions won because they had more points.

4 0
2 years ago
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Work out the mean.<br> 1, 3, 3. 4. 6, 9, 9
I am Lyosha [343]
1+3+3+4+6+9+9 is 35
7 numbers so divide by 7
35/7 = 5
Mean is 5
8 0
2 years ago
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Round 5049 correct to 1 significant figure​
Step2247 [10]

5000

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  • Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
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  • Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
  • Exponentiation (n^x) only rounds by the significant figures in the base.
  • To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
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<em>-</em><em> </em><em>BRAINLIEST </em><em>answerer</em><em> ❤️</em>

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