The answer is bwhich is 196
Isolate "x" on one side of the algebraic equation by dividing the number that appears on the same side of the equation as part of "x."
Answer:
20
Step-by-step explanation:
9.60 × 15= 144 9.60×5=48 15+5=20
Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
Factor the demoniator:-
x^2 -2x - 24 = (x - 6)(x + 4)
the asymptotes occurs when denominator = 0
so here they are the vertical lines x = 6 and x = -4
