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irga5000 [103]
2 years ago
7

Scientific notation of a length of 0.0000923

Mathematics
2 answers:
solong [7]2 years ago
8 0
The answer is ___ but only because ____ it was quite challenging not gonna lie
Tju [1.3M]2 years ago
5 0

Answer:

9.23 x 10^-5

Step-by-step explanation:

But the decimal point behind the first number that isn't 0

Then count how many times you moved it and that is the exponent on the ten

If you moved the decimal right, it is negative exponent

If you moved the decimal left, it is a positive exponent

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The equation of this circle is:
qaws [65]

Step-by-step explanation:

Equation : (x - 4)² + (y + 3)² = 4.

4 0
2 years ago
If 154 pounds is the lightest weight, then<br> pounds is the heaviest.<br> 170<br> 163<br> 169
Paha777 [63]

Answer:

169 Pounds

Step-by-step explanation:

...

3 0
3 years ago
Read 2 more answers
How many faces does the polyhedron have? _ faces How many vertices does the polyhedron have? _vertices How many edges does the p
Sindrei [870]

The polyhedron has:

6 Faces, 8 vertices and 12 edges <u>in</u><u> </u><u>total</u><u>.</u>

But

3 Faces, 7 vertices and 7 edges <u>are</u><u> </u><u>visible</u><u>.</u>

5 0
3 years ago
For the three-part question that follows, provide your answer to each question in the given workspace.
zepelin [54]

Answer:

See below

Step-by-step explanation:

Julie wants to cut her hair 9 inches off from 16 inches

<h3>Part A </h3>

Expression

  • 16 - 9
<h3>Part B</h3>

Calculation

  • 16 - 9 = 7 inches
<h3>Part C</h3>

Explanation of steps

  • 1 - note the point 16 on the number line
  • 2 - move left by 9 points on the number line
  • 3 - note point 7 as answer
6 0
3 years ago
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The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?
Paul [167]

Answer:

The standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Let (x_{1},y_{1}) and (x_{2},y_{2}) be the given points (6,2) and (-2,5) respectively.

M=(\frac{6-2}{2},\frac{2+5}{2})

M=(\frac{4}{2},\frac{7}{2})

M=(2,\frac{7}{2})

Therefore the center (h,k) is (2,\frac{7}{2})

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

=\sqrt{(-2-6)^2+(5-2)^2}

=\sqrt{(-8)^2+(3)^2}

=\sqrt{64+9}

=\sqrt{73}

Therefore the radius is \sqrt{73}

i.e., r=\sqrt{73}

Therefore the standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Now substituting the center  and radiuswe get

(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2

(x-2)^2+(y-\frac{7}{2})^2=73

Therefore the standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

5 0
3 years ago
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