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2 years ago

5

Does anyone know how to do this?

1 answer:

Gala2k [10]2 years ago

8 0

To find the midpoint of a line segment
Add both "x" coordinates, divide by 2.
Add both "y" coordinates, divide by 2.

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The graph shows the voltage in a circuit changing as temperature increases from 100° to 600°. which is the best estimate for the

Nataliya [291]

Answer:

3.5?

Step-by-step explanation:

6 0

2 years ago

Calculate cos(480°) and sin(480°).

hram777 [196]

Answer:

$\cos(480^\circ)=-\dfrac{1}{2}$

$\sin(480^\circ)=\dfrac{\sqrt{3}}{2}$

Step-by-step explanation:

Calculate the value of trigonometry function.

$\cos(480^\circ)$ and $\sin(480^\circ)$

Split the angle between 0 to 90° using trigonometry formula.

$\Rightarrow \cos(360^\circ+120^\circ)$

$\Rightarrow \cos(120^\circ)$ $\because \cos(360+\theta)=\cos\theta$

$\Rightarrow \cos(180^\circ-60^\circ)$ $\because 120=180-60$

$\Rightarrow -\cos(60^\circ)$ $\because \cos(180-\theta)=-\cos\theta$

$\Rightarrow -\dfrac{1}{2}$

Therefore, cos(480°) = -0.5

$\Rightarrow \sin(360^\circ+120^\circ)$

$\Rightarrow \sin(120^\circ)$ $\because \sin(360+\theta)=\sin\theta$

$\Rightarrow \sin(180^\circ-60^\circ)$ $\because 120=180-60$

$\Rightarrow \sin(60^\circ)$ $\because \sin(180-\theta)=\sin\theta$

$\Rightarrow \dfrac{\sqrt{3}}{2}$

Therefore, sin(480°) = 0.866

7 0

3 years ago

Lyons evaluated the expression analyze Leon’s work check all that apply

maria [59]

Answer: The answer is C, and D.

8 0

3 years ago

Read 2 more answers

Can someone plz help me??

Klio2033 [76]

If you are looking for the third angle it is 90 degrees

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BW%7D%20%3D%202" id="TexFormula1" title="\sqrt[4]{W} = 2" alt="\sqrt[4]{W} = 2

solmaris [256]

Answer:

<h2>W = 16</h2>

Step-by-step explanation:

<h3> $\sqrt[4]{W} = 2$ </h3>

To find W raise each of the sides of the equation to the power 4 to make W stand alone

That's

<h3> $( { \sqrt[4]{W} })^{4} = {2}^{4}$ </h3>

We have

W = 2⁴

We have the final answer as

<h3>W = 16</h3>

Hope this helps you

6 0

3 years ago