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MrRissso [65]
3 years ago
7

At some department store, all suits are reduced 30% from the retail price. If a man purchased a suit that originally rera ec for

262.40. how much did he save?
He saved $ (Round to the nearest cent as needed.)
Mathematics
1 answer:
Arisa [49]3 years ago
5 0

Answer:

$78.72

Step-by-step explanation:

To find 30% of the original value, we need to turn this percentage into a decimal or a fraction and then multiply it by the original value

  • 30% is equivalent to 0.30, \frac{30}{100}, and \frac{3}{10}
  • So we can use either of these values. I will use 0.30 for simplicity

  • ($262.40)(0.30) = $78.72 is the amount saved
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If an item you own is damaged or stolen, insurance will give you money to replace it.
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Factorise 3c^2-c<br><br><br> Please help me quick
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c(3c - 1)

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3 years ago
PLEASE HELP ME WITH THIS
Alik [6]

Answer:

  • x + y ≤ 600
  • 5x +7y ≥ 3500
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Step-by-step explanation:

a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.

  x + y ≤ 600 . . . . . . . limit imposed by available seating

  5x +7y ≥ 3500 . . . . required revenue to meet expenses

__

b) For x = 330, the first inequality puts one limit on y:

  330 +y ≤ 600

  y ≤ 270

And the second inequality puts another limit on y:

  5(330) +7y ≥ 3500

  7y ≥ 1850 . . . . subtract 1650

  y ≥ 264.3 . . . . divide by 7

The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.

4 0
3 years ago
A TV has a listed price of $885.98 before tax. If the sales tax rate is 8.5%, find the total cost of the TV with sales tax
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Answer:

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8 0
3 years ago
Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
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Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

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In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t    Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0
3 years ago
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