Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
Answer:
x=39
Step-by-step explanation:
Answer: i think its B
Step-by-step explanation:
Step-by-step explanation:
y = mx + b
Your equation is y = 3/5x, which means you're "missing" the B
Whichhhhh, just means you're starting at (0,0)
- Now, m represents the slope. So your slope was given right off the bat, 3/5.
- You start at (0,0) and you count up 3, and right 5. Or you could do down 3 and left 5
- This gives you a line with a slope of 3/5
Hopefully my drawing kind of explains it better
