Question

What is the distance between A and B? Round your answer to the nearest hundredth. A coordinate plane is shown. Point A is located at negative 2, 4, and point B is located at 2, 0. A line segment connects the two points. 4.56 5.35 5.66 6.10 i just want the answer please

Answer 1

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

In this problem we have

$A(x1,y1)=(-2,4)\\B(x2,y2)=(2,0)$

substitute in the formula

$d=\sqrt{(0-4)^{2}+(2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(4)^{2}}$

$d=\sqrt{32}\ units$

Round to the nearest hundredth

$d=\sqrt{32}\ units=5.66\ units$

therefore

the answer is

the distance is equal to $5.66\ units$

Answer 2

What are the answers?