Question

Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 units 3 units 6 units A (5, 4) and B( 5, -2) arrowRight E(-2, -1) and F(-2, -5) arrowRight C(-4, 1) and D(1, 1) arrowRight G(3, -5) and H(6, -5) arrowRight

Answer 1

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

$d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

$d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}$

$d(A,B) = \sqrt{(0)^2+(-6)^2}$

$d(A,B) = \sqrt{36}$

$d(A,B) = 6$

Distance between points A (5, 4) and B( 5, -2) is 6 units

b)  E (-2, -1) and F( -2, -5)

the distance formula is:

$d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

$d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}$

$d(E,F) = \sqrt{(0)^2+(-4)^2}$

$d(E,F) = \sqrt{16}$

$d(E,F) = 4$

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c)  C (-4, 1) and D( 1, 1)

the distance formula is:

$d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

$d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}$

$d(C,D) = \sqrt{(5)^2+(0)^2}$

$d(C,D) = \sqrt{25}$

$d(C,D) = 5$

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

$d(G,H) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

$d(G,H)= \sqrt{(6-(3))^2+(-5-(-5))^2}$

$d(G,H) = \sqrt{(3)^2+(0)^2}$

$d(G,H) = \sqrt{9}$

$d(G,H) = 3$

Distance between points G(3, -5) and H(6, -5) is 3 units