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grigory [225]
2 years ago
12

how many cards from a standard deck must be drawn to guarantee atleast 3 cards of the same suit have been drawn, pidgeon hole

Mathematics
1 answer:
Natalka [10]2 years ago
3 0

The number of cards which must be drawn from the standard deck is 12.

Given a standard deck of cards.

We have to find the number of  cards to be drawn so that we will get atleast 3 cards from each suit. Because they have used atleast in the question so the cards can be more also so we have to reach at minimum level of cards to be drawn to guarantee atleast 3 cards of the same suit.

Number of suits in a  standard deck= 4 (Clubs, Hearts, Diamond,  Spades)

Cards in 1 suit=13

We need atleast 3 cards of the  same suit so we need atleast 3*4=12 cards. (3 from each suit)

Hence the minimum cards which must be drawn to get atleast 3 cards of the same suit is 12.

Learn more about cards at brainly.com/question/5858025

#SPJ4

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The coordinates of an ordered pair have opposite signs. In which quadrant(s) must the ordered pair lie? Explain.
rusak2 [61]
Quadrant 2 or 4. All points in quadrant 1 are both positive, all points in quadrant 3 are both negative.
4 0
3 years ago
What are the solutions of 3x2 - x + 4 =
o-na [289]

To do this, you must use the order of operations.

3·2=6

6+4=10

Now to solve (-)x.

Since -x comes in front of 4, you must make your equation:

-x+10

Nothing is written for x, so now, you have the answer.

-x+10

8 0
3 years ago
What are the answers
dlinn [17]

Answer:

See below

Step-by-step explanation:

The ratio of the secants is the same when set up as full length to external length.

Formula

MN/LN = QN/PN

Givens

LN = 22 + 14 = 36

MN = 14

PN = 32

QN = x

Solution

14/36 = x / (32)  Multiply both sides by 32

14*32 / 36 = x    Combine 14 and 32

448/36 = x         Divide by 36 and switch

x = 12.4

Answers

PN (External) = 13 is the closest answer

Length LN = 36

6 0
3 years ago
A consumer affairs investigator records the repair cost for 4 randomly selected washers. A sample mean of $64.26 and standard de
Mashutka [201]

Answer:

Critical value: z = 1.28

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.80}{2} = 0.10

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

So

M = 1.28*\frac{27.77}{\sqrt{4}} = 17.773

The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.

The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

7 0
2 years ago
john is looking at a map with a scale of 1/4 inch=20 miles. he measured the distance from his home to the bowling alley in town
Sergio039 [100]
1 inch=80mi

2.5*80mi=200 mi
5 0
2 years ago
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