Which of the ordered pairs in the form (x, y) is a solution of this equation? 5x-y/3 = 13 (2, -9), (3, -6)
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Given
R is the interior of ∠ TUV.
m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.
Find the value of x and the m ∠TUV.
To proof
As given in the question
m ∠TUV=3x+16, and m ∠TUR=x+10
thus
m∠ RUV = m∠ TUV - m∠ TUR
= 3x + 16 - x -10
= 2x + 6
As given
m ∠RUV=30°
compare both the values
we get
30 = 2x + 6
24 = 2x
12 = x
put this value in the m ∠TUV= 3x+16
m ∠TUV= 12× 3 +16
= 52°
Hence proved
Answer:
i. Slope=-1/6
ii. Midpoint= (1,8.5)
iii. <em>Distance</em><em>=</em><em> </em><em>√</em><em>3</em><em>7</em><em> </em><em>units</em>
<em>iv.</em><em> </em><em> </em><em> </em><em> </em><em>Slope </em><em>of </em><em>t=</em><em>2</em>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
Answer:
36
Step-by-step explanation:
The maximum height is the y-coordinate of the vertex
given a quadratic in standard form : ax² + bx + c : a ≠ 0
then the x-coordinate of the vertex is
= -
y = - x² + 20x - 64 is in standard form
with a = - 1, b = 20 and c = - 64, hence
= -
= 10
substitute x = 10 into the equation for y
y = - (10)² + 20(10) - 64 = 36 ← max height