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3 years ago

I’m kinda confused .. any help ?

Mathematics

1 answer:

Troyanec [42]3 years ago

3 0

Answer:

Oo this is tricky I wanna say C and E maybe Im sorry if it's wrong.

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The formula for the surface area of a pyramid is: SA=1/2LP+B . which equation solves formula for p

jeka94

$S_A=\frac{1}{2}LP+B\\\\\frac{1}{2}LP+B=S_A\ \ \ \ \ \ |subrtact\ "B"\ from\ both\ sides\\\\\frac{1}{2}LP=S_A-B\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\LP=2S_A-2B\ \ \ \ \ \ |divide\ both\ sides\ by\ "L"\\\\P=\frac{2S_A-2B}{L}$

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4 years ago

Helppppppppppppppppp

Maksim231197 [3]

$\huge \tt༆ Answer ༄$

The respective terms used for the lines are ~

a.) Line a = Tangent

b.) Line b = Radius

c.) Line c = Diameter

d.) Line d = Secant

3 0

3 years ago

Read 2 more answers

A)y

prohojiy [21]

The answer would be B, due to the fact that the shaded area is above the line.

8 0

3 years ago

2. Two puppies together weigh 22 kilograms 300 grams. If one

monitta

Answer:

B = 12800 grams or 12kg 800 grams.

Step-by-step explanation:

Let the two puppies be A and B respectively.

Translating the word problem into an algebraic expression, we have;

A + B = 22kg 300g

A = 9kg 500g

Conversion;

1 Kilograms = 1000 grams.

9kg 500g = 9*1000 + 500 = 9500 grams

22kg 300g = 22*1000 + 300 = 22300 g

Substituting into the above formula, we have;

9500 + B = 22300

B = 22300 - 9500

B = 12800 grams or 12kg 800 grams

6 0

3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

3 years ago

Read 2 more answers