Answer:
Toner = $45.00; ink = $25.50
Step-by-step explanation:
Let T = the cost of a toner cartridge and I = the cost of an ink cartridge
We have two conditions:
(1) T = I + 19.50
(2) 4T + 11I = 460.50 Substitute (1) into (2)
4(I + 19.50) + 11I = 460.50 Remove parentheses
4I + 78.00 + 11I = 460.50 Combine like terms
15 I + 78.00 = 460.50 Subtract 78.00 from each side
15I = 382.50 Divide each side by 15
(3) I = 25.50
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Substitute (3) into (1)
T = 25.50 + 19.50
T = 45.00
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<em>Check:
</em>
(1) 45.00 = 25.50 + 19.50
45.00 = 45.00
(2) 4×45.00 + 11×25.50 = 460.50
180.00 + 280.50 = 460.50
460.50 = 460.50
This is an easy half-life problem.
Every half-life, a substance loses half its radioactivity. So, after 2 half-lives, a substance will have a quarter of its radioactivity.
2 * 5,700 = 11,400 years
answer is C
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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Answer:
Can you please put the figure, radius, or diameter?
Step-by-step explanation:
-3 x -26 = 78
meaning the answer is D.
The reason the answer is D, is because two negatives when multiplied or divided become positive. Only when multiplied or divided does this occur.
