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3 years ago

Help asap fast

Mathematics

1 answer:

dlinn [17]3 years ago

3 0

The answer is B.24x^6-18x^5=6x^5(4x-3)

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You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of t

natka813 [3]

Hello AljakeVillena!

$\huge \boxed{\mathfrak{Question} \downarrow}$

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

mass of crate = 50 kg
Force you pull it with = 450 N
Frictional force = 250 N
Acceleration = ?

__________________

Let's first find the total force/net force acting on the crate. The total force will be :-

450 N - 250 N = 200 N.

We subtracted the forces because both the forces act on opposite directions.

__________________

Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..

Acceleration = Force/mass
a = F/m
a = 200/50
a = 4 m/s²

__________________

So, the acceleration of the crate is 4 m/s².

__________________

Hope it'll help you!

ℓu¢αzz ッ

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vovikov84 [41]

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anygoal [31]

Answer:

$\frac{2}{3}$

Explanation:

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We know that the answer has to be a fraction with the denominator of 3. Take a look at the denominator of $\frac{8}{12}$ - it's 12. Ask yourself: 12 divided by what number equals 3? That number would 4.

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Step-by-step explanation:

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